If the denominator of a fraction is x + 1, for what value of x is the fraction undefined?

Answer 1

Let's set up an example fraction as x/y. The fraction x/y will be undefined when we cannot get a real number back from dividing x by y. Oftentimes this is represented by dividing by zero. Dividing by zero is not possible, therefore giving us an undefined fraction: x/0.

In your question, we have the fraction (some number)/x+1. For this fraction to be undefined, we must set the denominator equal to zero. This leaves us with:

x+1=0

Subtract 1 from both sides of the equation to isolate the x and you get:

x=-1

Therefore, the value of x that gives you an undefined fraction with the denominator x+1 is -1.

Let me know if you have any further questions and I'll do my best to help. Thanks!