Maclaurin Series

Question

Find the second derivative of f at x = 0 if the Maclaurin series for f(x) = 1 - 9x + 16x^2 - 25x^3 + …

Type the answer as an integer using a hyphen, -, for negative values.

(f''(0)x^2)/2!=16x^2

f''(0)/2=16

f''(0)=32

Please check my answer and thank you in advance!

Answer 1

f(x) = 1 - 9x + 16x² - 25x³ + ...

f'(x) = -9 + 32x - 75x² + ...

f"(x) = 32 - 150x + ...

So, f"(0) = 32