Raymond B. answered 04/28/21
Math, microeconomics or criminal justice
Face cards are K,Q and J, 3 out 13 cards in each of the 4 suits. that's probability of 3/13 of getting a face card. Subtract that from 1
1-3/13 = 13/13 -3/13 = 10/13
10/13 = 40/52
There are 3x4= 12 face cards. 12/52 = odds of getting a face card
subtract that from 1
1-12/52 = 52/52 - 12/52 = 40/52 = probability of not getting a face card
= about 77% chance of not getting a face card
Unless you meant one card has been removed from the deck before drawing a card
then your deck now has 51 cards. but the card that was first removed from the deck already had odds of 40/52 of not being a face card. The odds don't change on drawing a card from the now 51 cards remaining. Odds are (10/13)(51)/51
=10/13 =40/52
Unless you meant the first card removed was a face card, leaving odds of a non-face card on the next draw to be 40/51
Having a test on Thursday is 20% if classes are 5 days a week.
It's more objective if you have historical data, such as if there has never been a test given on a Thursday, then odds are low it will happen. If every test ever given was on a Thursday, odds are very high another test will be on a Thursday.
You could also check to see if holidays are falling on a Thursday, such as Thanksgiving. Then odds are less than 20%. But if more holidays are on Mondays and Fridays, then maybe Thursdays are higher than 20%
Sam L.
I dont get the, 1-3/13 = 13/13 -3/13 = 10/13 when you subtract the 1 anf get 13/13, and why would you subtract 1 from the 3 face cards in one suit04/28/21