A 15.0 Ω resistor is hooked up to a 12.0 V battery in a circuit with a closed switch.

Question

a)   Draw a circuit diagram for the circuit described. Label all parts and values.

b)   What is the current flowing through the resistor?

c)   What is the power dissipated by the resistor?

Answer 1

B)ohms law state that the voltage ina circuit is directly proportional to the current flowing through the circuit and also proportional to the resistance in that circuit.

Therefore we'll have an algebraic representation of that law as V=IR

Where V is the voltage

I is the current

R is the resistance

To get I as the subject of formula we simply divide both sides by I

I=V/R

THerefor we have I= 12/15 = 4/5 amperes.

C) power=IxV=I²R=V²/R

I peak the first equation which is p=IV.

Substituting for I and V would give us

4/5×12 which would give us 48/5 watt