A rocket skateboard of mass 3.00 kg has an initial velocity of (5.00, 2.50) m/s. A net force of (3.40, 2.67) N is applied to it for 10.0 s. what's the velocity?

Question

Its asking for the velocity at the end of the time but i have never encountered two velocities and forces together inside parantheses

Answer 1

So, if this is the case, then you can compute the x and y results separately using F= ma in the x, and y directions:

 

a= F/m

A_x= F_x/M  and similarly for the y component.

 

For x:

 

V_x(t)= V_x(0) + (F_x/M)*t = 5.00 m/s + (3.40 N / 3.00 kg) * 10.0 s

 

similarly for the y component. Recall that a N is a Kg-m/s²