Raymond B. answered 04/27/21
Math, microeconomics or criminal justice
9(x^3 -3 ) = 9x^3 - 27 is probably what you want
or factor further into 3 terms: 9(x^3-3) = 9(x-3^1/3)(x^2 +(3^1/3)x + (3^1/3)^2/3) if you use the general formula for the difference in cubes = a^3-b^3 = (a-b) times (a^2+ab+b^2) where a=x and b=3^1/2= cube root of 3.
or maybe you really intended to write 9(x^(3-3)) = 9(x^0) = 9(1) = 9. that would have been a nearly trick question if that were the problem