A rectangular parking lot is 60 ft longer than it is wide. Find the dimensions of the parking lot if it measures 300 ft diagonally.

Answer 1

300^2 = W^2 + (60+W)^2 = W^2 +W^2 + 120W + 3600

hypotenuse squared = sum of squares of the other two sides

2W^2 + 120 = 90,000-3600

divide by 2

W^2 +60 = 45000-1800

complete the square

W^2 + 60 + 900 = 43200+900

(W+30)^2 = 44100

W+30 = sqr44100 = 210

W = 210-30 = 180 feet wide

L = 240 feet long

180^2 + 240^2 = 300^2

It's a 3-4-5 right triangle increased by a factor of 60