convert (x+3)^2+(y+3)^2=18

Question

I need to convert (x+3)^2 + (y+3)^2 =18 to polar form and am stuck. I know the x=rcos theta and y = rsin theta rule.

Answer 1

Use that conversion of x and y to trigonometric functions and substitute into the given equation (either in given form or multiplied out).

Simplify and solve for r.