Algebra 2 factoring

Question

After see there is not gcf what would you do first to factor 6m²-13m+6 and how draw complete asterisk what will be answer.

Answer 1

6(x-2/3)(x-3/2) = 6(x^2 -2x/3-3x/2 + 6/6) = 6(x^2 -4x/6 -9x/6 +1) = 6(x^2-13x/6+1) = 6x^2 -13x + 6

(6)(x-2/3)(x-3/2)= 6x^2-13x+6

use the quadratic formula

x =-b/2a + or - (1/2a)sqr(b^2-4ac) where a=6, b=-13, and c=6, that gives x=2/3 or 3/2, change their sign and stick an x in front of them to get (x-2/3)(x-3/2) multiply that by 6 to get the original trinomial.