A positive integer squared plus 10 times its consecutive integer is equal to 34

Answer 1

x^2 + 10(x+1) = 34

x^2 +10x +10 = 34

x^2 +10x -24 = 0

(x+12)(x-2) = 0

x = 2 or -12

x+1 = 3 or -11

2^2 + 10(3) = 34

(-12)^2 + 10(-11) = 144-110

but you only want the positive integers: 2 and 3