Quadratic Formula

Question

A throw by Kallie is modeled to be: y = x2 +6x +4 .y = x2 +6x +4 .Use the quadratic formula x =−b±(b2√−4ac)2ax =-b±(b2-4ac)2a

What is the answer to this? It is a short answer question.

Answer 1

So here we have the equation y=x² + 6x + 4 and we are asked to solve it by using the quadratic formula, which is x=[-b±√(b² -4ac)] /2a . This is what we know.

y=ax²+bx+c

y=1x² + 6x + 4 a=1 , b=6 , c=4 Now, we can plug th values in the equation.

x=[-1±√(6²-4(1)(4))] / 2(1) = -1±√36 -16 / 2 = -1±√20 / 2 = -1± 2√5 /2

So we have two answers

x=(-1+2√5)/2 and x= (-1-2√5)/2