Write the equation in standard form for the circle with center (8,3) and radius 4.

Answer 1

(x-h)^2 + (y-k)^2 = r^2 where (h,k) = (8,3) and r=4, h=8, k=3

(x-8)^2 + (y-3)^2 = 4^2 is standard from for the circle's equation

Answer 2

Hi Kay!

The equation of a circle with center at (h,k) and a radius of r is:

(x−h)²+(y−k)²=r²

In this example h=8, k=3 and r=4, so after substituting into above formula we have:

(x−8)²+(y−3)²= 4²

(x−8)²+(y−3)² =16​

The answer is (x−8)²+(y−3)² =16​