2l + 2w = 42
2(l + w) = 42
l + w = 21
l = 21 - w
lw = 108
w(21 - w) = 108
21w - w2 = 108
w2 - 21w + 108 = 0
Mark C.
asked 04/23/21The perimeter of a rectangle is 42 ft. The area of the rectangle is 108 ft^2. Create and solve an equation to find the dimensions of the rectangle.
2l + 2w = 42
2(l + w) = 42
l + w = 21
l = 21 - w
lw = 108
w(21 - w) = 108
21w - w2 = 108
w2 - 21w + 108 = 0
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