need help o this math problem

Question

Suppose you are solving equations in the interval [0, 2ϖ). Without actually solving equations, what is the difference between the number of solutions of sin x = ½ and sin (2x) = ½, How do you account for this difference?

Answer 1

2x = twice x

twice as many soluutions for sinx=1/2

2 solutions for sinx=1/2

just 1 solution for sin2x = 1/2