J.R. S. answered 04/22/21
Ph.D. University Professor with 10+ years Tutoring Experience
Metal oxide + acid ==> salt + H2O
Copper(I) oxide = Cu2O
Copper(II) oxide = CuO
Vinegar = acetic acid = CH3COOH
Copper acetate = CH3COOCu
1). Cu2O + 2CH3COOH ==> 2CH3COOCu + H2O
2). CuO + 2CH3COOH ==> (CH3COO)2Cu + H2O