
Yefim S. answered 04/21/21
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Math Tutor with Experience
Here order dose not play role.
So we have combinations C(42,4) = 42!/(4!·38!) = 42·41·40·39/(4·3·2·1) = 111930
Kyla S.
asked 04/21/21Yefim S. answered 04/21/21
Math Tutor with Experience
Here order dose not play role.
So we have combinations C(42,4) = 42!/(4!·38!) = 42·41·40·39/(4·3·2·1) = 111930
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