Find the distance between C (5,1) and D (3,6).

Answer 1

distance = square root of 29 = about 5.4

(5,1) (3,6)

distance squared = sum of squares of the x and y differences

d^2 = (6-1)^2 + (3-5)^2 = 5^2 + 2^2 = 25+4 = 29

d= square root of 29 = about 5.4

and just in case there might be other questions on the same problem:

line through the points has slope = m = (6-1)/(3-5) = 5/-2 = -5/2

y=mx + b

y =-5x/2 + b, plug in either point to solve for b

1=(-5/2)(5) + b

b =1+25/2 = 27/2

y=-5x/2 + 27/2 in slope intercept standard form

or if you want to eliminate fractions, multiply by 2 to get

2y=-5x +27 or if you want to eliminate negative signs

5x+2y = 27