You use the cosine law to find a, then the sin law to find B and C.
cos law a = sqrt(b^2 + c^2 - 2bc cos A)
sin law sin B/b = sin A/a, or B = arcsin(b sin A)/a)
C = arcsin(c sin A/a)
Kendra K.
asked 04/20/21Solve for the remaining angles and side of the triangle described below. Round to the nearest thousandth:
A=75°, c=4, b=2
a-
C-
B-
You use the cosine law to find a, then the sin law to find B and C.
cos law a = sqrt(b^2 + c^2 - 2bc cos A)
sin law sin B/b = sin A/a, or B = arcsin(b sin A)/a)
C = arcsin(c sin A/a)
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