if f(x)=-2(x+1)^2 and g(x)=f(x-3)+5 what is the vertex of g(x)

Answer 1

vertex of g(x) is (2,5)

f(x) = -2((x+1)^2)

f(x-3) = -2(x-3+1)^2 = -2(x-2)^2

g(f(x-3)) = -2(x-2)^2 + 5

standard vertex form is g(x) = a(x-h)^2 + k where (h,k) = vertex = (2,5)