
David D. answered 04/18/21
Science and Math Tutor with a PhD in Physics
Lets start by writing down all our information.
μ = 57
σ = 10
μ and σ have a normal distribution.
32≤X≤62
The first thing we need to do is calculate a Z score for X = 32 and X = 62. The formula is Z = (x-μ)/σ.
Plugging in 32 and 62 for X we get Z1 = -2.5 and Z2 = 0.5. Now the Z score is a measure of how many standard deviations x is from a Normalized normal distribution (μ = 0, σ = 1). The probability is the area under this normalized normal distribution. Using a Z table or a calculator (or google) we can look up the area under the curves for Z≤-2.5 and Z≤0.5. We get 0.0062 for Z1 and 0.6915 for Z2. Now those values are the areas under the curve for Z≤-2.5 (X≤-32) and Z≤0.5 (X≤62). We want the area in between so that is just 0.6915 - 0.0062 = 0.6853 or 68.53%.