Please with these problems!

Question

1. f(x)=x^2-2x+3; f(x)=-6x
2. f(x)=x^2-2x+3; f(x)=-2x+28

Answer 1

1) subtract the equations : f-f = x²-2x+3 - (-6x)

simplify we get : 0 = x²+4x+3

Solve 0 = x²+4x+3 using quadratic formula which gives the answer x= -1, x= -3

Place the solutions x= -1, x= -3 into f = x² -2x+3

for f = x² -2x+3, substitute x with -1 : f=6

for f = x² -2x+3, substitute x with -3: f= 18

The final solutions are x= -1, x= -3, f=6, f=18

2) Subtract the equations : f-f = x² -2x+3 - (-2x+28)

simplify we get : 0= x²-25

solve 0=x²-25 using quadratic formula which gives us x=5, x=-5

for f = x² -2x+3, substitute x with 5 : f=18

for f = x² -2x+3: substitute x with -5: f =38

The final solutions are x=5, x=-5, f=18, f= 38