find the 10th term of the geometric sequence whose common ratio is 2/3 and whose first term is 8.

Question

Please help! Here is another question:

Find the 7th term of the geometric sequence whose common ratio is 2/3 and whose first term is 6.

Answer 1

When you see the phrase "geometric sequence", always remember to use the formula an=a1(r)^(n-1). Where a1 is the initial term, n is the number of term, and r is the ratio.

Let's look at the first case, we were given n=10, r=2/3, and a1=8. Now plug it in!. a10=8(2/3)^(10-1), the answer should be .208 (rounded to the 3 decimal places).

Similarly, for your other question, you were given n=7, r=2/3, a1=6. Hope you can solve this on your own. Just plug it in and you will have the answer. Answer should be .527 (rounded to the 3 decimal places).