Catelyn B.

asked • 04/14/21

write the equation of the line that passes through (-6,-3) and (3,3)

Murray B.

To find the equation of the line use the Point-Slope form: y - y(1) = m(x - x(1)) x(1) and y(1) are the coordinates of one point, in which 2 points are given. You can select either one. The x and y are variables and don't require numbers to be substituted into them. That leaves the m, which needs to be solved for. m is the slope of the line, which is the vertical distance between two points divided by the horizontal distance between the two points. The formula is as follows: m =[ y(2) - y(1) ] / [ x(2) - x(1) ]. From the given points, x(1) = -6; y(1) = -3; x(2) = 3; y(2) = 3. Substitute these values into the formula and solve for m. m = [3 - (-3) ] / [ 3 - (-6) ]; m = (3 + 3) / 3 + 6); m = 6/9; m = 2/3 Now, we have all the values to substitute into the point-slope form: y - y(1) = m[ x - x(1) ] (I will use the point (3,3), but you can also use (-6,-3) y - 3 = 2/3( x - 3 ) y - 3 = 2/3x - 2/3(3/1) y - 3 = 2/3x - 2 y - 3 + 3 = 2/3x - 2 + 3 y = 2/3x + 1 This is the equation of the line. Let's try the point-slope form using the other point (-6,-3) y - (-3) = 2/3( x - (-6)) y + 3 = 2/3x + 2/3(6/1) y + 3 = 2/3x + 4 y + 3 - 3 = 2/3x + 4 - 3 y = 2/3x + 1 Here is the equation again.
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04/18/21

1 Expert Answer

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Eric H. answered • 04/14/21

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