Graph and solve The following inequalities.

Question

1. Y ≥ -3x + 4

2. Y ≥ -x - 5

3. Y ≥ 4/3x - 4

Please help i don't get it

Answer 1

First, just treat them as equalities. graph the lines

y=-3x +4

y=-x-5

y=(4/3)x-4

then shade in the areas above each line and look

for where the shaded areas intersect.

the 2nd line is redundant. You really just need to look

where the 1st and 3rd lines intersect and shade in the area

above it and above the 1st & 3rd lines. That's the solution set, that area

they intersect when -3x+4 = (4/3)x-4 or

where (13/3)x = 8 or x=(3/13)(8) = 24/13 and y=-3(24/13)+4 = -20/13

or about the point (1.8,-1.5) Shade everything above that, above the two

lines (1st & 3rd line) Ignore the 2nd line.

Or, in other words, for x>24/13, shade above the 3rd line

and for x<24/13, shade above the 1st line

3rd line is upward sloping. 1st is downward sloping and they

intersect when x=24/13