Raymond B. answered 06/25/25
Tutor
5
(2)
Math, microeconomics or criminal justice
4x^2y^3/2xy^5 = 2x/y^2
= 4/2 * x^(2-1) * y^(3-5) = 2xy^-2 = 2x/y^2
Amanda M.
asked 04/10/214x2y3\2xy5 please answer soon. Thank you
Raymond B. answered 06/25/25
Math, microeconomics or criminal justice
4x^2y^3/2xy^5 = 2x/y^2
= 4/2 * x^(2-1) * y^(3-5) = 2xy^-2 = 2x/y^2
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