The answer is 2(x-5)(x+1)/(x-4)
The 2x2 in the numerator with the x in denominator gives what you have called a slant asymptote of 2x.
The two factors in the numerator give you the 2 zeros and the numerator is -10 and the denominator is -4 when x=0.
Rochelle K.
asked 04/10/21Write an equation to match the function.
vertical asymptote: x = 4
slant asymptote: y = 2x
Create a function that matches the graph --- on the graph I see one line crosses through the point (5, 0). The other line passes through (-1, 0) and (0, 2.5).
I do not know how to write this function, can someone please help?
The answer is 2(x-5)(x+1)/(x-4)
The 2x2 in the numerator with the x in denominator gives what you have called a slant asymptote of 2x.
The two factors in the numerator give you the 2 zeros and the numerator is -10 and the denominator is -4 when x=0.
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