When f is shifted 3 units up to create the graph of g, each output value of f increases by 3 units to form the corresponding output in g. For the function f, if x is the input , then f(x) the output.
Therefore,
(A) g(x) = f(x) + 3
When the graph of f is steeper than the graph of g - this means that the graph of g is less steeper as compared to the graph of f . For example, if f(x) is a linear function with slope m, then g(x) is a linear function with slope n < m.
If f(x) is a quadratic function with a co-efficient M, then g(x) will be the quadratic function with the co-efficient M /N where N ≠ 0 and N > M and the graph of g(x) is not as sharp a U shape as compared to f(x)
Yeah, to keep it simple, in general, we can say that g is compressed by a factor a = M/ N, and of course a<1.
Therefore,
(B) g(x) = a f(x)
For example if f(x) = x, then g(x)=(1/2) f(x) ; if f(x)= 2x2, then g(x) = (2/4) x2
which is equivalent to g(x)=(1/2)x2.
When the graph of f is shifted 3 units down to create g- This is pretty straight forward and opposite situation to (A)
Therefore
(C) g(x) = f(x) -3
When the graph of f is less steep, than the graph of g - This is a situation opposite to that in (B) :- this means that the graph of g is steeper than the graph of f which means the same as saying g is vertically stretched .
Therefore,
(D) g(x) = b f(x) , where b = M•N ( M, N as in case B)
For example, if f(x) = x, then g(x) = 2x ; if f(x) = 2x2, then g(x) = 6x2.
Lia W.
Thank you04/09/21