The bullseye on an archery target has a radius of 3 inches.

Question

The entire target has a radius of 9 inches. To the nearest hundredth, find the area of the target outside of the bullseye. Use 3.14 for π.

Answer 1

Area of bull's eye is 9pi

Area of target is 81pi

Area of difference is (81-9)pi = 72pi = about 226.08 in^2 if you use 3.14=pi

But if you use a more accurate pi = 3.14159 then Area = 226.19