E P.

asked • 04/05/21

Chemistry Help Please

3Al (s) + 3NH4ClO4 -->Al2O3(s) + AlCl3 (s) + 3NO (g) + 6H2O (l)

1)Which reactant is the limiting reactant if 4.25 g of Al is mixed with 5.46 g of NH4ClO4

2)How many grams of Al2O3 can be produced from the conditions above ( theoretical yield)

3) what is the actual yield of Al2O3 in grams if the percent yield is 68.2%

1 Expert Answer


J.R. S.

Dr. Bob...not sure where you got 1.34 moles of NH4ClO4. Using a molar mass of 117.5 g/mol I get 0.0465 moles.


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