What passes through (-1,-8) and perpendicular to x+3y=-6

Answer 1

Given line:

x + 3y = -6

3y = -6 - x

y = (-6/3) - (x/3)

y = -2 - (1/3)x

y = -(1/3)x - 2

slope of the given line: -1/3

The slope of two perpendicular lines are inverse-reciprocals, so:

slope of new line: m = 3

Equation of a line: y = mx + b

Replacing the given point (-1, -8):

-8 = 3 ( -1) + b

-8 = -3 + b

-8 + 3 = b

-5 = b

Equation of the new line that passes through point (-1, -8), with slope 3:

y = 3x -5

Answer 2

Line has slope of degree 1 in R2 space. Rectangular equation is y=3x+1.

Answer 3

The perpendicular line has slope 3

and that line is 3 = (y+8)/(x+3) ... which can be manipulated into any necessary form.