Which equation BEST fits the data in the given table?

Question

0-4000

1-2000

2-1000

3-500

4-250

5-125

6-62.5

A. F(x) = 2,000(1/2)^x

B. F(x) = 4,000(2)^2

C. F(x) = 4,000(1/2)^x

D. F(x) = 1/2(4,000)^x

Answer 1

The data starts at 4000 and then is halved for every value of x. (C) seems to be the appropriate answer.

F(0) = 4000 (1/2)⁰ = 4000(1) = 4000

F(1) = 4000 (1/2)¹ = 4000/2 = 2000

F(2) = 4000/4 = 1000

F(3) = 4000/8 = 500

---etc---