Algebra one story problems

Question

an investor invested a total of $2,100 in two mutual funds. One fund earned a 8% profit while the other earned a 5% profit. If the investor's total profit was $111, how much was invested in each mutual fund?

Answer 1

.08X + .05(2100-X) = 111

.08X-.05X = 111 - .05(2100)

.03X = 111- 105 = 6

X = 6/.03 = $200 invested at 8%

2100-X = 2100-200 = $1900 invested at 5%

.08 x 200 = 16

.05 x 1900 = 95

1900 + 95 = 111

111/2100 = about 5.3%, which is much closer to 5% than to 8%. Most will be invested at 5%