If y varies inversely as x^2, and x = 10 while y = 1/4, find x when y = 1.

Answer 1

y = k/x^2, where k is the constant of variation we need to determine

1/4 = k/10^2

1/4 = k/100

25 = k

so

y = 25/x^2

when y = 1

1 = 25/x^2

x^2 = 25

x = 5