Raymond B. answered 03/31/21
Math, microeconomics or criminal justice
f(x) = x^3
g(x) = 1/(x+1)
fog(x) = [1/(x+1)]^3 = 1/(x^3+3x^2+3x+1)
gof(x) = 1/(x^3+1)
fog(x) = gof(x)
1/(x^3+3x^2 +3x + 1) = 1/(x^3 + 1)
x^3 + 3x^2 +3x + 1 = x^3 + 1
3x^2 +3x = 0
x(x+1) = 0
x = 0 (x=-1 would be another solution, except it makes g(x) undefined, 1/(-1+1) = 1/0)