The critical number is x1.
x3 = x1 + 5
x2= 4 * x3 = 4x1 + 20
The sum of the 3 numbers is 133. Now plug in the expression for the 3 numbers and solve for x1.
Then you have expressions for the other 2.
Mouni S.
asked • 03/30/21the sum of three numbers is 133. the third number is 5 more than the first. the second number is 4 times the third. what are the numbers
Can someone please help me !?
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