Raymond B. answered 03/28/21
Math, microeconomics or criminal justice
You could graph the two equations
y=3 is a flat horizontal line
y=-2x^2+2 is a downward opening parabola with y intercept at y=2 or the point (0,2) which is also the vertex and maximum point.
The solution is where the two lines intersect, but they don't intersect as y=3 is above the maximum point of the parabola. There is no real solution. But there are imaginary solutions. They come in conjugate pairs.
y=y
-2x^2 + 2 = 3
x = + or - (1/-4)sqr(0^2 - 4)(-2)(-1) = + or - (1/4)sqr-8 = + or - (i/2)sqr2
2x^2 -2 = -3
2x^2 = -1
x^2 = -1/2
x = + square root of -1/2 = + or - isqr(1/2)
x = + (i/2)sqr2
check the solution
y=3 = -2x^2 +2 = -2[(i/2)sqr2] + 2
1 = -2[(i/2)sqr2]^2 = (2/4)2 = 1