Suppose two trains leave a station at the same time, traveling in opposite directions. Train B faster than Train A in 4.5 hours, the trains are 414 miles apart. Find the speed of each train

Answer 1

d = rt

d/t = rate of speed

414/4.5 = 92 miles per hour which is the sum of their 2 speeds

Train A's speed is < 92/2 = 46 mph

Train B, the faster train's speed > 46 mph

IF they had gone at the same speed, each would have gone 46x4.5 = 207 miles

which is half the distance of 414

If one goes faster than 46 mph, the other is going less than 46 mph

if one were going zero mph, the other would go 92 mph

if Train A went 23 mph, then in 4.5 hours it went 103.5 miles

and Train B would go 414-103.5 = 310.5 miles in 4.5 hours or 310.5/4.5 = 69 mph

69+23 = 92 mph

IF Train B goes X mph, Train A goes 92-X mph

Train B's speed is between 46 and 92 mph

Train A's between 0 and 46