Raymond B. answered 02/25/23
Math, microeconomics or criminal justice
A = amplitude = 5
B=2pi/period = 2pi/6/2= 2pi/3
C = phase shift =
D = midline = 0
h(t) = AsinB(t-C) + D
= 5sin[(2pi/3)(t)]
h(t) = 5sin[2pi/3)(t)] = 4
sin2tpi/3 = 4/5
2tpi/3 = sin^-1(4/5) = 53.13
t = 53.13(3/2pi) = 25.37 seconds
but as the period = 3 seconds
it's also at 4 cm in ..., 22.37, 19.37, 16.37, 13.37, 10.37, 7.37, 4.37, 1.37 seconds
or t= 1.37 + 3n seconds where n= any integer