Help!!!! Please

Question

What is the negative solution for this equation

-2x^2-6x=-8

Answer 1

-2x² - 6x = -8

Rewrite:

-2x² - 6x + 8 = 0

Solve with quadratic formula: x_1,2 = (-b ± √b² - 4ac) / 2a

x_{1, 2} = (-(-6) ± √(-6)² - 4 (-2) (8)) / 2 (-2)

x_{1, 2} = (6 ± √36 + 64) / -4

x_{1, 2} = (6 ± √100) / -4

x_{1, 2} = (6 ± 10) / -4

x₁ = (6 + 10) / -4

x₁ = 16 / -4

x₁ = -4

x₂ = (6 - 10) / -4

x₂ = -4 / -4

x₂ = 1

The negative solution is x = -4

Answer 2

2x² + 6x - 8 = 0

2(-8) = -16

What two factors of -16 have a sum of 6? We just almost had them.

-2(8) = -16 and -2 + 8 = 6

2x² - 2x + 8x - 8 = 0

2x(x - 1) + 8(x - 1) = 0

(2x + 8)(x - 1) = 0

2x + 8 = 0

2x = -8

x = -4

Well, that's negative.

x - 1 = 0

x = 1

Answer 3

Rewrite

-2x²-6x + 8 = 0

x²+3x-4 = 0

From Quadratic equation:

x = (-3±√(9-4(-4)))/2 = (-3±√25)/2 = (-3±5)/2

The negative solution = -8/2 = -4

Or by factoring

(x+4)(x-1) --> x = -4, 1

x = -4

Answer 4

-2x²-6x=-8

-2x²-6x+8 =0

divide by -2 to make the equation simpler

x²+3x-4=0

Find which 2 numbers multiplies to -4 and adds to +3.It is 4 &-1

so our factors are

(x+4)(x-1)=0

so by zero property of multiplication

x+4 =0

x=-4

or

x-1 =0

x=1

So our negative x- value is -4