Graph the function. F(x)=sqrt x-2, plot four points on the graph of the function: the leftmost point and three additional points

Answer 1

y=sqr(x-2)

y^2 = x-2

vertex = (2,0)

x=(y-0)^2 +2

x=(y-k)^2 + h where (h,k) = (2,0) = vertex = left most point, x>2 If x were less than 2 you'd have the square root of a negative number and no real solution. axis of symmetry y=0 or the x axis

(3,1) is on the parabola, or the top half of it

(6,2) is on the parabola

(11,3) is on the parabola

UNLESS you really meant y=(sqrx) -2

then sqrx = y+2

x = (y+2)^2 = y^2 +2y + 4

x intercept = 4 or the point (4,0)

vertex = (0,-2) = also the leftward most point

y intercept = -2

axis of symmetry is y=-2

other points on the parabola are

(9,1), (16,2), (25,23),