Which equation could be solved to find the width, w, of the rectangle?

Question

The length of a rectangle is 3 inches longer than the twice the width. The perimeter of the rectangle is 36 inches. Which equation could be solved to find the width, w, of the rectangle? *

3w + 3 = 36

2w + 3 = 36

4w + 6 = 36

6w + 6 = 36

Answer 1

4W + 6 = 36

4W = 30

W = 30/4 = 7.5 inches wide

L=3+W = 10.5 inches long

36 = 2(L+W) = 2(10.5 + 7.5) = 2(18) = 36