What is the pH of a 0.0011M solution of Ca(OH)2?

Answer 1

Ca(OH)2 is a slightly soluble (~ 0.025 M) base. So, at 0.0011 M, it would be soluble.

Ca(OH)2 ==> Ca2+ + 2OH-

[OH-] = 2 x 0.0011 M = 0.0022 M

pOH = -log 0.0022

pOH = 2.66

pH = 14 - pOH = 14 - 2.66

pH = 11.34