Investment rate

Question

A man invested $16,000. Part of it was invested at 2%, and the rest was invested at 6%. His

     yearly interest was $592. How much was invested at each rate?

Answer 1

2X + 6(16-x) = 59.2

-4X = 59.2 -96 = -36.8

X = 36.98/4 = 9.2K = $9,200 invested at 2%

16-X = 16K-9.2K = $6,800 invested at 6%

Answer 2