Find the sum of three consecutive, positive, odd integers such that two times the product of the first and middle integers minus 12 times the third integer is 42.

Answer 1

2(x-2)(x) - 12(x+2) = 42

2x^2 -4x - 12x -24 = 42

2x^2 - 16x - 66 = 0

x^2 - 8x - 33 = 0 factor to get

(x-11)(x+3) = 0

x = 11 (ignore -3)

the 3 consecutive odd integers are

9, 11, and 13

2(9+11) - 12(13) = 42

198 - 156= 42