find the common difference if the first term of an arithmetic sequence is 2 and the 11th term is 9.5

Answer 1

The nth term, a_{n ,} can be expressed as a_n = a₁ + (n-1)d, where a₁ is the first term and d is the common difference.

So, we have 2 + 10d = 9.5

10d = 7.5

d = 0.75 = 3/4

Answer 2

d = (9.5 - 2)/(11-1) = 7.5/10 = 0.75 = 3/4 = the common difference

a1 =2

a2 = 2.75

a3 = 3.5

a4 =4.25

a5 = 5

a6 = 5.75

a7 = 6.5

a8 = 7.25

a9 = 8

a10 = 8.75

a11 = 9.5

Answer 3

d = (9.5 - 2)/(11-1) = 7.5/10 = 0.75 = 3/4 = the common difference

a1 =2

a2 = 2.75

a3 = 3.5

a4 =4.25

a5 = 5

a6 = 5.75

a7 = 6.5

a8 = 7.25

a9 = 8

a10 = 8.75

a11 = 9.5