Complete the square for the x-terms and for the y-terms:
(x2 + 8x) + (y2 - 12y) = -29
(x2 + 8x + 16) + (y2 - 12y + 36) = -29 + 16 + 36
(x+4)2 + (y-6)2 = 23
This is a circle with center (-4,6) and radius √23
Lil H.
asked 03/22/21x2 +8x+y2-12y=-29
Complete the square for the x-terms and for the y-terms:
(x2 + 8x) + (y2 - 12y) = -29
(x2 + 8x + 16) + (y2 - 12y + 36) = -29 + 16 + 36
(x+4)2 + (y-6)2 = 23
This is a circle with center (-4,6) and radius √23
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