A farm has chickens and cows. The chickens have 2 legs. The cows have 4 legs. Altogether, there are 50 legs on the farm.

Answer 1

2Ch + 4C = 50

Ch + 2C = 25

max cows are 12 with 1 chjcken

max chickens are 23 with 1 cow

1 cow 23 chickens

2 cows 21 chickens

3 cows 19 chickens

4 cows 17 chickens

5 cows 15 chickens

6 cows 13 chickens

7 cows 11 chickens

8 cows 9 chickens

9 cows 7 chickens

10 cows 5 chickens

11 cows 3 chickens

12 cows 1 chicken

Usually this type of problems gives on additional piece of information, the total number of cows & chickens

C + Ch = X

then you have 2 equations 2 unknowns and can solve for a unique solution

Ch+ 2C =25

Ch + C =X

C =25-X = number of cows