Let x be the horizontal distance from the base of the ladder to the wall. Let y be the vertical distance from the base of the wall to the top of the ladder. x and y are the legs of a right triangle and are related in this way:
x2 + y2 = 312 ; y = 10 , x = √861 , dx/dt = 5 , dy/dt = ?
2x·dx/dt + 2y·dy/dt = 0
10√861 + 20 dy/dt = 0
dy/dt = - √861 / 2 ft/sec