Raymond B. answered 03/19/21
Math, microeconomics or criminal justice
W = 15 + L
L= W-15
P/2 = 82/2 = 41 = L+W = W-15 + W = 2W -15
2W - 15 = 41
2W = 41+15 = 56
W =56/2 = 28 inches wide
Jennnifer H.
asked 03/19/21A rectangle has a perimeter of 82 inches. The width of the rectangle is 15 inches more than the length. What is the width, in inches, of the rectangle?
Raymond B. answered 03/19/21
Math, microeconomics or criminal justice
W = 15 + L
L= W-15
P/2 = 82/2 = 41 = L+W = W-15 + W = 2W -15
2W - 15 = 41
2W = 41+15 = 56
W =56/2 = 28 inches wide
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