if a1 = 1 and an+1 = (an)^2 + 3 then find the value of a4

Answer 1

a₁ = 1

a_n+1 = (a_n)²+3

a₂ = 1²+3 = 4

a₃= 4²+3 = 19

a₄ = 19²+3 = 361+3 = 364

Answer 2

a1 = 1

a2 = 1^2 + 3 = 4

a3 = 4^2 + 3 = 19

a4 = 19^2 + 3 = 364

Answer 3

This is a recursive series, where the next term is found by using the one before it.

a1=1 Plug a1 into the formula provided to find a2

a2=(1)²+3=4 Plug in a2 into the formula provided to find a3

a3=(4)²+3=19 Plug in a3 into the formula provided to find a4

a4=(19)²+3=364